Integrand size = 19, antiderivative size = 134 \[ \int \frac {1}{(d+e x)^3 \left (b x+c x^2\right )} \, dx=-\frac {e}{2 d (c d-b e) (d+e x)^2}-\frac {e (2 c d-b e)}{d^2 (c d-b e)^2 (d+e x)}+\frac {\log (x)}{b d^3}-\frac {c^3 \log (b+c x)}{b (c d-b e)^3}+\frac {e \left (3 c^2 d^2-3 b c d e+b^2 e^2\right ) \log (d+e x)}{d^3 (c d-b e)^3} \]
-1/2*e/d/(-b*e+c*d)/(e*x+d)^2-e*(-b*e+2*c*d)/d^2/(-b*e+c*d)^2/(e*x+d)+ln(x )/b/d^3-c^3*ln(c*x+b)/b/(-b*e+c*d)^3+e*(b^2*e^2-3*b*c*d*e+3*c^2*d^2)*ln(e* x+d)/d^3/(-b*e+c*d)^3
Time = 0.25 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.87 \[ \int \frac {1}{(d+e x)^3 \left (b x+c x^2\right )} \, dx=\frac {\log (x)}{b d^3}+\frac {\frac {2 c^3 \log (b+c x)}{b}+\frac {e \left (\frac {d (c d-b e) (-b e (3 d+2 e x)+c d (5 d+4 e x))}{(d+e x)^2}-2 \left (3 c^2 d^2-3 b c d e+b^2 e^2\right ) \log (d+e x)\right )}{d^3}}{2 (-c d+b e)^3} \]
Log[x]/(b*d^3) + ((2*c^3*Log[b + c*x])/b + (e*((d*(c*d - b*e)*(-(b*e*(3*d + 2*e*x)) + c*d*(5*d + 4*e*x)))/(d + e*x)^2 - 2*(3*c^2*d^2 - 3*b*c*d*e + b ^2*e^2)*Log[d + e*x]))/d^3)/(2*(-(c*d) + b*e)^3)
Time = 0.38 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.10, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {1141, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {1}{\left (b x+c x^2\right ) (d+e x)^3} \, dx\) |
| \(\Big \downarrow \) 1141 |
| \(\displaystyle c \int \left (-\frac {c^3}{b (c d-b e)^3 (b+c x)}+\frac {1}{b d^3 x c}+\frac {e^2 \left (3 c^2 d^2-3 b c e d+b^2 e^2\right )}{d^3 (c d-b e)^3 (d+e x) c}+\frac {e^2 (2 c d-b e)}{d^2 (c d-b e)^2 (d+e x)^2 c}+\frac {e^2}{d (c d-b e) (d+e x)^3 c}\right )dx\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle c \left (\frac {e \left (b^2 e^2-3 b c d e+3 c^2 d^2\right ) \log (d+e x)}{c d^3 (c d-b e)^3}-\frac {c^2 \log (b+c x)}{b (c d-b e)^3}+\frac {\log (x)}{b c d^3}-\frac {e (2 c d-b e)}{c d^2 (d+e x) (c d-b e)^2}-\frac {e}{2 c d (d+e x)^2 (c d-b e)}\right )\) |
c*(-1/2*e/(c*d*(c*d - b*e)*(d + e*x)^2) - (e*(2*c*d - b*e))/(c*d^2*(c*d - b*e)^2*(d + e*x)) + Log[x]/(b*c*d^3) - (c^2*Log[b + c*x])/(b*(c*d - b*e)^3 ) + (e*(3*c^2*d^2 - 3*b*c*d*e + b^2*e^2)*Log[d + e*x])/(c*d^3*(c*d - b*e)^ 3))
3.3.66.3.1 Defintions of rubi rules used
Int[((d_.) + (e_.)*(x_))^(m_.)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_ Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Simp[1/c^p Int[ExpandIntegrand[ (d + e*x)^m*(b/2 - q/2 + c*x)^p*(b/2 + q/2 + c*x)^p, x], x], x] /; EqQ[p, - 1] || !FractionalPowerFactorQ[q]] /; FreeQ[{a, b, c, d, e}, x] && ILtQ[p, 0] && IntegerQ[m] && NiceSqrtQ[b^2 - 4*a*c]
Time = 2.09 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.98
| method | result | size |
| default | \(\frac {\ln \left (x \right )}{b \,d^{3}}+\frac {c^{3} \ln \left (c x +b \right )}{\left (b e -c d \right )^{3} b}+\frac {e}{2 d \left (b e -c d \right ) \left (e x +d \right )^{2}}+\frac {e \left (b e -2 c d \right )}{d^{2} \left (b e -c d \right )^{2} \left (e x +d \right )}-\frac {e \left (b^{2} e^{2}-3 b c d e +3 c^{2} d^{2}\right ) \ln \left (e x +d \right )}{d^{3} \left (b e -c d \right )^{3}}\) | \(131\) |
| norman | \(\frac {\frac {\left (-2 e^{2} b +3 c d e \right ) e x}{d^{2} \left (b^{2} e^{2}-2 b c d e +c^{2} d^{2}\right )}+\frac {\left (-3 e^{2} b +5 c d e \right ) e^{2} x^{2}}{2 d^{3} \left (b^{2} e^{2}-2 b c d e +c^{2} d^{2}\right )}}{\left (e x +d \right )^{2}}+\frac {\ln \left (x \right )}{b \,d^{3}}+\frac {c^{3} \ln \left (c x +b \right )}{b \left (b^{3} e^{3}-3 b^{2} d \,e^{2} c +3 b \,c^{2} d^{2} e -c^{3} d^{3}\right )}-\frac {e \left (b^{2} e^{2}-3 b c d e +3 c^{2} d^{2}\right ) \ln \left (e x +d \right )}{d^{3} \left (b^{3} e^{3}-3 b^{2} d \,e^{2} c +3 b \,c^{2} d^{2} e -c^{3} d^{3}\right )}\) | \(230\) |
| risch | \(\frac {\frac {e^{2} \left (b e -2 c d \right ) x}{d^{2} \left (b^{2} e^{2}-2 b c d e +c^{2} d^{2}\right )}+\frac {e \left (3 b e -5 c d \right )}{2 d \left (b^{2} e^{2}-2 b c d e +c^{2} d^{2}\right )}}{\left (e x +d \right )^{2}}+\frac {c^{3} \ln \left (c x +b \right )}{b \left (b^{3} e^{3}-3 b^{2} d \,e^{2} c +3 b \,c^{2} d^{2} e -c^{3} d^{3}\right )}+\frac {\ln \left (-x \right )}{d^{3} b}-\frac {e^{3} \ln \left (-e x -d \right ) b^{2}}{d^{3} \left (b^{3} e^{3}-3 b^{2} d \,e^{2} c +3 b \,c^{2} d^{2} e -c^{3} d^{3}\right )}+\frac {3 e^{2} \ln \left (-e x -d \right ) b c}{d^{2} \left (b^{3} e^{3}-3 b^{2} d \,e^{2} c +3 b \,c^{2} d^{2} e -c^{3} d^{3}\right )}-\frac {3 e \ln \left (-e x -d \right ) c^{2}}{d \left (b^{3} e^{3}-3 b^{2} d \,e^{2} c +3 b \,c^{2} d^{2} e -c^{3} d^{3}\right )}\) | \(321\) |
| parallelrisch | \(\frac {-2 \ln \left (x \right ) c^{3} d^{5}+6 \ln \left (e x +d \right ) b^{2} c \,d^{3} e^{2}-6 \ln \left (e x +d \right ) b \,c^{2} d^{4} e -3 x^{2} b^{3} e^{5}+2 \ln \left (c x +b \right ) c^{3} d^{5}-6 \ln \left (x \right ) x^{2} b^{2} c d \,e^{4}+6 \ln \left (x \right ) x^{2} b \,c^{2} d^{2} e^{3}+6 \ln \left (e x +d \right ) x^{2} b^{2} c d \,e^{4}-6 \ln \left (e x +d \right ) x^{2} b \,c^{2} d^{2} e^{3}-12 \ln \left (x \right ) x \,b^{2} c \,d^{2} e^{3}+12 \ln \left (x \right ) x b \,c^{2} d^{3} e^{2}+12 \ln \left (e x +d \right ) x \,b^{2} c \,d^{2} e^{3}-12 \ln \left (e x +d \right ) x b \,c^{2} d^{3} e^{2}-4 x \,b^{3} d \,e^{4}+2 \ln \left (x \right ) x^{2} b^{3} e^{5}-2 \ln \left (e x +d \right ) x^{2} b^{3} e^{5}+2 \ln \left (x \right ) b^{3} d^{2} e^{3}-2 \ln \left (e x +d \right ) b^{3} d^{2} e^{3}+8 x^{2} b^{2} c d \,e^{4}-5 x^{2} b \,c^{2} d^{2} e^{3}+10 x \,b^{2} c \,d^{2} e^{3}-6 x b \,c^{2} d^{3} e^{2}-2 \ln \left (x \right ) x^{2} c^{3} d^{3} e^{2}+2 \ln \left (c x +b \right ) x^{2} c^{3} d^{3} e^{2}+4 \ln \left (x \right ) x \,b^{3} d \,e^{4}-4 \ln \left (x \right ) x \,c^{3} d^{4} e +4 \ln \left (c x +b \right ) x \,c^{3} d^{4} e -4 \ln \left (e x +d \right ) x \,b^{3} d \,e^{4}-6 \ln \left (x \right ) b^{2} c \,d^{3} e^{2}+6 \ln \left (x \right ) b \,c^{2} d^{4} e}{2 \left (b^{3} e^{3}-3 b^{2} d \,e^{2} c +3 b \,c^{2} d^{2} e -c^{3} d^{3}\right ) b \left (e x +d \right )^{2} d^{3}}\) | \(506\) |
ln(x)/b/d^3+c^3/(b*e-c*d)^3/b*ln(c*x+b)+1/2*e/d/(b*e-c*d)/(e*x+d)^2+e*(b*e -2*c*d)/d^2/(b*e-c*d)^2/(e*x+d)-e*(b^2*e^2-3*b*c*d*e+3*c^2*d^2)/d^3/(b*e-c *d)^3*ln(e*x+d)
Leaf count of result is larger than twice the leaf count of optimal. 506 vs. \(2 (132) = 264\).
Time = 4.25 (sec) , antiderivative size = 506, normalized size of antiderivative = 3.78 \[ \int \frac {1}{(d+e x)^3 \left (b x+c x^2\right )} \, dx=-\frac {5 \, b c^{2} d^{4} e - 8 \, b^{2} c d^{3} e^{2} + 3 \, b^{3} d^{2} e^{3} + 2 \, {\left (2 \, b c^{2} d^{3} e^{2} - 3 \, b^{2} c d^{2} e^{3} + b^{3} d e^{4}\right )} x + 2 \, {\left (c^{3} d^{3} e^{2} x^{2} + 2 \, c^{3} d^{4} e x + c^{3} d^{5}\right )} \log \left (c x + b\right ) - 2 \, {\left (3 \, b c^{2} d^{4} e - 3 \, b^{2} c d^{3} e^{2} + b^{3} d^{2} e^{3} + {\left (3 \, b c^{2} d^{2} e^{3} - 3 \, b^{2} c d e^{4} + b^{3} e^{5}\right )} x^{2} + 2 \, {\left (3 \, b c^{2} d^{3} e^{2} - 3 \, b^{2} c d^{2} e^{3} + b^{3} d e^{4}\right )} x\right )} \log \left (e x + d\right ) - 2 \, {\left (c^{3} d^{5} - 3 \, b c^{2} d^{4} e + 3 \, b^{2} c d^{3} e^{2} - b^{3} d^{2} e^{3} + {\left (c^{3} d^{3} e^{2} - 3 \, b c^{2} d^{2} e^{3} + 3 \, b^{2} c d e^{4} - b^{3} e^{5}\right )} x^{2} + 2 \, {\left (c^{3} d^{4} e - 3 \, b c^{2} d^{3} e^{2} + 3 \, b^{2} c d^{2} e^{3} - b^{3} d e^{4}\right )} x\right )} \log \left (x\right )}{2 \, {\left (b c^{3} d^{8} - 3 \, b^{2} c^{2} d^{7} e + 3 \, b^{3} c d^{6} e^{2} - b^{4} d^{5} e^{3} + {\left (b c^{3} d^{6} e^{2} - 3 \, b^{2} c^{2} d^{5} e^{3} + 3 \, b^{3} c d^{4} e^{4} - b^{4} d^{3} e^{5}\right )} x^{2} + 2 \, {\left (b c^{3} d^{7} e - 3 \, b^{2} c^{2} d^{6} e^{2} + 3 \, b^{3} c d^{5} e^{3} - b^{4} d^{4} e^{4}\right )} x\right )}} \]
-1/2*(5*b*c^2*d^4*e - 8*b^2*c*d^3*e^2 + 3*b^3*d^2*e^3 + 2*(2*b*c^2*d^3*e^2 - 3*b^2*c*d^2*e^3 + b^3*d*e^4)*x + 2*(c^3*d^3*e^2*x^2 + 2*c^3*d^4*e*x + c ^3*d^5)*log(c*x + b) - 2*(3*b*c^2*d^4*e - 3*b^2*c*d^3*e^2 + b^3*d^2*e^3 + (3*b*c^2*d^2*e^3 - 3*b^2*c*d*e^4 + b^3*e^5)*x^2 + 2*(3*b*c^2*d^3*e^2 - 3*b ^2*c*d^2*e^3 + b^3*d*e^4)*x)*log(e*x + d) - 2*(c^3*d^5 - 3*b*c^2*d^4*e + 3 *b^2*c*d^3*e^2 - b^3*d^2*e^3 + (c^3*d^3*e^2 - 3*b*c^2*d^2*e^3 + 3*b^2*c*d* e^4 - b^3*e^5)*x^2 + 2*(c^3*d^4*e - 3*b*c^2*d^3*e^2 + 3*b^2*c*d^2*e^3 - b^ 3*d*e^4)*x)*log(x))/(b*c^3*d^8 - 3*b^2*c^2*d^7*e + 3*b^3*c*d^6*e^2 - b^4*d ^5*e^3 + (b*c^3*d^6*e^2 - 3*b^2*c^2*d^5*e^3 + 3*b^3*c*d^4*e^4 - b^4*d^3*e^ 5)*x^2 + 2*(b*c^3*d^7*e - 3*b^2*c^2*d^6*e^2 + 3*b^3*c*d^5*e^3 - b^4*d^4*e^ 4)*x)
Timed out. \[ \int \frac {1}{(d+e x)^3 \left (b x+c x^2\right )} \, dx=\text {Timed out} \]
Leaf count of result is larger than twice the leaf count of optimal. 266 vs. \(2 (132) = 264\).
Time = 0.22 (sec) , antiderivative size = 266, normalized size of antiderivative = 1.99 \[ \int \frac {1}{(d+e x)^3 \left (b x+c x^2\right )} \, dx=-\frac {c^{3} \log \left (c x + b\right )}{b c^{3} d^{3} - 3 \, b^{2} c^{2} d^{2} e + 3 \, b^{3} c d e^{2} - b^{4} e^{3}} + \frac {{\left (3 \, c^{2} d^{2} e - 3 \, b c d e^{2} + b^{2} e^{3}\right )} \log \left (e x + d\right )}{c^{3} d^{6} - 3 \, b c^{2} d^{5} e + 3 \, b^{2} c d^{4} e^{2} - b^{3} d^{3} e^{3}} - \frac {5 \, c d^{2} e - 3 \, b d e^{2} + 2 \, {\left (2 \, c d e^{2} - b e^{3}\right )} x}{2 \, {\left (c^{2} d^{6} - 2 \, b c d^{5} e + b^{2} d^{4} e^{2} + {\left (c^{2} d^{4} e^{2} - 2 \, b c d^{3} e^{3} + b^{2} d^{2} e^{4}\right )} x^{2} + 2 \, {\left (c^{2} d^{5} e - 2 \, b c d^{4} e^{2} + b^{2} d^{3} e^{3}\right )} x\right )}} + \frac {\log \left (x\right )}{b d^{3}} \]
-c^3*log(c*x + b)/(b*c^3*d^3 - 3*b^2*c^2*d^2*e + 3*b^3*c*d*e^2 - b^4*e^3) + (3*c^2*d^2*e - 3*b*c*d*e^2 + b^2*e^3)*log(e*x + d)/(c^3*d^6 - 3*b*c^2*d^ 5*e + 3*b^2*c*d^4*e^2 - b^3*d^3*e^3) - 1/2*(5*c*d^2*e - 3*b*d*e^2 + 2*(2*c *d*e^2 - b*e^3)*x)/(c^2*d^6 - 2*b*c*d^5*e + b^2*d^4*e^2 + (c^2*d^4*e^2 - 2 *b*c*d^3*e^3 + b^2*d^2*e^4)*x^2 + 2*(c^2*d^5*e - 2*b*c*d^4*e^2 + b^2*d^3*e ^3)*x) + log(x)/(b*d^3)
Time = 0.28 (sec) , antiderivative size = 234, normalized size of antiderivative = 1.75 \[ \int \frac {1}{(d+e x)^3 \left (b x+c x^2\right )} \, dx=-\frac {c^{4} \log \left ({\left | c x + b \right |}\right )}{b c^{4} d^{3} - 3 \, b^{2} c^{3} d^{2} e + 3 \, b^{3} c^{2} d e^{2} - b^{4} c e^{3}} + \frac {{\left (3 \, c^{2} d^{2} e^{2} - 3 \, b c d e^{3} + b^{2} e^{4}\right )} \log \left ({\left | e x + d \right |}\right )}{c^{3} d^{6} e - 3 \, b c^{2} d^{5} e^{2} + 3 \, b^{2} c d^{4} e^{3} - b^{3} d^{3} e^{4}} + \frac {\log \left ({\left | x \right |}\right )}{b d^{3}} - \frac {5 \, c^{2} d^{4} e - 8 \, b c d^{3} e^{2} + 3 \, b^{2} d^{2} e^{3} + 2 \, {\left (2 \, c^{2} d^{3} e^{2} - 3 \, b c d^{2} e^{3} + b^{2} d e^{4}\right )} x}{2 \, {\left (c d - b e\right )}^{3} {\left (e x + d\right )}^{2} d^{3}} \]
-c^4*log(abs(c*x + b))/(b*c^4*d^3 - 3*b^2*c^3*d^2*e + 3*b^3*c^2*d*e^2 - b^ 4*c*e^3) + (3*c^2*d^2*e^2 - 3*b*c*d*e^3 + b^2*e^4)*log(abs(e*x + d))/(c^3* d^6*e - 3*b*c^2*d^5*e^2 + 3*b^2*c*d^4*e^3 - b^3*d^3*e^4) + log(abs(x))/(b* d^3) - 1/2*(5*c^2*d^4*e - 8*b*c*d^3*e^2 + 3*b^2*d^2*e^3 + 2*(2*c^2*d^3*e^2 - 3*b*c*d^2*e^3 + b^2*d*e^4)*x)/((c*d - b*e)^3*(e*x + d)^2*d^3)
Time = 10.01 (sec) , antiderivative size = 235, normalized size of antiderivative = 1.75 \[ \int \frac {1}{(d+e x)^3 \left (b x+c x^2\right )} \, dx=\frac {\frac {3\,b\,e^2-5\,c\,d\,e}{2\,d\,\left (b^2\,e^2-2\,b\,c\,d\,e+c^2\,d^2\right )}+\frac {e^2\,x\,\left (b\,e-2\,c\,d\right )}{d^2\,\left (b^2\,e^2-2\,b\,c\,d\,e+c^2\,d^2\right )}}{d^2+2\,d\,e\,x+e^2\,x^2}+\frac {c^3\,\ln \left (b+c\,x\right )}{b^4\,e^3-3\,b^3\,c\,d\,e^2+3\,b^2\,c^2\,d^2\,e-b\,c^3\,d^3}+\frac {\ln \left (d+e\,x\right )\,\left (b^2\,e^3-3\,b\,c\,d\,e^2+3\,c^2\,d^2\,e\right )}{-b^3\,d^3\,e^3+3\,b^2\,c\,d^4\,e^2-3\,b\,c^2\,d^5\,e+c^3\,d^6}+\frac {\ln \left (x\right )}{b\,d^3} \]
((3*b*e^2 - 5*c*d*e)/(2*d*(b^2*e^2 + c^2*d^2 - 2*b*c*d*e)) + (e^2*x*(b*e - 2*c*d))/(d^2*(b^2*e^2 + c^2*d^2 - 2*b*c*d*e)))/(d^2 + e^2*x^2 + 2*d*e*x) + (c^3*log(b + c*x))/(b^4*e^3 - b*c^3*d^3 + 3*b^2*c^2*d^2*e - 3*b^3*c*d*e^ 2) + (log(d + e*x)*(b^2*e^3 + 3*c^2*d^2*e - 3*b*c*d*e^2))/(c^3*d^6 - b^3*d ^3*e^3 + 3*b^2*c*d^4*e^2 - 3*b*c^2*d^5*e) + log(x)/(b*d^3)